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民国初年，杀富济贫的江湖大侠李三，被北洋政府在京斩首，师弟李显劫法场未遂，便独撑“燕子门”避祸关东，十年苦练。十年过后，三个弟子长大成人，个个身怀绝技，师徒四人先后来到济南。 师弟李云龙暗恋师姐李云馨而师姐却一心爱恋忠厚耿直的师兄李云飞。李云龙为民众泄愤，斩下恶霸王大兽人头，金钱豹视“燕子门”为眼中钉，设擂台与“燕子门”比武一争高低，结果在李云龙手下成为丧家之犬，日本武士高岛挑战“燕子门”却屡战屡败，气急败坏。李云龙偷走警察局长谭家麟与日本勾结的密文，并将密文登报公布于众，又偷走了韩复榘的金表，令韩十分光火，与谭家麟密谋缉“燕子李三”。百姓争说“燕子李三”又回来了，说书生铁嘴霸王说李三，令“燕子李三”名声大振。我说我没迟到你聋了吗。在一次偶然中，路小北与肖枫在一张游戏地图中跨时空相遇。身处不同时空的两人从互相怀疑到彼此信任。他们各自组建战队，共同研究战术，帮助对方成长。梦想从未曾容易过，职业电竞选手之路更是不易，无数次重复枯燥的训练，一次次被命运打落谷底，他们却从未放弃。不同的时代，相同的热血青春。In addition to solving the port problem of A, the serial number problem also needs to be paid attention to. The serial number corresponds to the sliding window. The fake TCP packet needs to be filled with the serial number. If the value of the serial number is not in the sliding window of B when it is sent to B before A, B will actively discard it. So we need to find the serial number that can fall into the sliding window between AB at that time. This can be solved violently, because the length of a sequence is 32 bits, and the value range is 0-4294967296. If the window size is like 65535 under Windows I caught in the above figure, I only need to divide, and I know that at most I only need to send 65537 (4294967296/65535=65537) packets to have a sequence number fall into the sliding window. The desired value can be calculated quickly by exhaustion on multiple control hosts.As shown in the above code, when the button is clicked once, the div of showcount will be automatically increased by 1. As shown above, how to use the communication problem between the two modules in the publish-subscribe mode is demonstrated.　　五色帆船上，脱尘献上汗血宝马，希望紫衣侯能够去大宛国当国师，被紫衣侯一口拒绝；青木堡少主木郎神君向紫衣侯求取解药也被拒绝；只有“黄河狂侠”王巅几经劝服了紫衣侯为中原武林和大藏比武，最终大藏因下盘不稳中剑落入大海。